Searched refs:noOverlappingCount (Results 1 – 1 of 1) sorted by relevance
156 int noOverlappingCount = 0; in notIntersectsOrFullyContains() local164 noOverlappingCount++; in notIntersectsOrFullyContains()170 return (emptyCount + noOverlappingCount) == mSurfaces.length; in notIntersectsOrFullyContains()