Searched refs:submenu (Results 1 – 2 of 2) sorted by relevance
461 @NonNull MenuBuilder parent, @NonNull MenuBuilder submenu) { in findMenuItemForSubmenu() argument464 if (item.hasSubMenu() && submenu == item.getSubMenu()) { in findMenuItemForSubmenu()482 @NonNull CascadingMenuInfo parentInfo, @NonNull MenuBuilder submenu) { in findParentViewForSubmenu() argument483 final MenuItem owner = findMenuItemForSubmenu(parentInfo.menu, submenu); in findParentViewForSubmenu()
1dictionary=main:nl,locale=nl,description=Nederlands,date=1414726258, ...